Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
41 comments Page 5 of 5.
Chegen Ch Sangma said:
3 months ago
To find the absolute minimum radius of a horizontal curve, we use the standard highway engineering formula:
R = V2127(e+f)R = 127(e+f)V2.
R = V2127(e+f)R = 127(e+f)V2.
Where:
RR = radius (in meters).
VV = design speed (km/h).
ee = superelevation (maximum, usually 0.07 or 7%).
ff = lateral friction (maximum, usually 0.15).
Given:
V = 60 km/h.
e = 0.07e = 0.07,
f = 0.15f = 0.15.
Calculation: R = 602127(0.07 + 0.15)R = 127(0.07+0.15)602R.
= 3600127 × 0.22R.
= 127 × 0.223600R.
= 360027.94.
≈ 128.8 mR.
= 27.943600 ≈ 128.8m✅ Final Answer:
Absolute minimum radius ≈ 129 m.
R = V2127(e+f)R = 127(e+f)V2.
R = V2127(e+f)R = 127(e+f)V2.
Where:
RR = radius (in meters).
VV = design speed (km/h).
ee = superelevation (maximum, usually 0.07 or 7%).
ff = lateral friction (maximum, usually 0.15).
Given:
V = 60 km/h.
e = 0.07e = 0.07,
f = 0.15f = 0.15.
Calculation: R = 602127(0.07 + 0.15)R = 127(0.07+0.15)602R.
= 3600127 × 0.22R.
= 127 × 0.223600R.
= 360027.94.
≈ 128.8 mR.
= 27.943600 ≈ 128.8m✅ Final Answer:
Absolute minimum radius ≈ 129 m.
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