Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
40 comments Page 4 of 4.
Shyamlal said:
5 years ago
Equation for super Elevation:
e+f=v*v/225R(design speed),
So R=v*v/225(e+f),
Take e=0.07 & f=0.15,
R=60*60/225(0.07+0.15),
It get R=72.72m.
So the answer is option D.
ie =60*60/225.
e+f=v*v/225R(design speed),
So R=v*v/225(e+f),
Take e=0.07 & f=0.15,
R=60*60/225(0.07+0.15),
It get R=72.72m.
So the answer is option D.
ie =60*60/225.
Rafeek said:
5 years ago
Option D None of above.
The compensate gradients is 4 degree for, so the radius will be 60 x 4 = 120m.
The compensate gradients is 4 degree for, so the radius will be 60 x 4 = 120m.
Sugumar said:
5 years ago
How can we guess the weather it is a mixed traffic or single traffic. Can anyone explain based on this question?
Sanku said:
5 years ago
The right value is 128.84 meter.
(1)
Pooja m said:
5 years ago
Can we use e=(0.75V)*2/gr this formula?
r = (0.75*16.67) * 2/9.81 * 0.07,
r = 227.62.
r = (0.75*16.67) * 2/9.81 * 0.07,
r = 227.62.
(2)
Akshay said:
4 years ago
Factor 225 as kph, so answer 72.
Agree @Shyamlal.
Agree @Shyamlal.
(4)
Deepankar said:
4 years ago
For absolute minimum or ruling minimum radius we have to use V^2/127(e+f).
Where, V=speed in KMPH, e=given superelevation or according to given terrain condition (as there is none in this case so we HAVE TO assume plain for which it is 7% or 0.07) f = coefficient of lateral friction( 0.15).
R(absolute minimum)= (60)^2/127(0.07+0.15)= 128.84~129m.
Where, V=speed in KMPH, e=given superelevation or according to given terrain condition (as there is none in this case so we HAVE TO assume plain for which it is 7% or 0.07) f = coefficient of lateral friction( 0.15).
R(absolute minimum)= (60)^2/127(0.07+0.15)= 128.84~129m.
(16)
Sahil said:
2 years ago
The Correct ans is 128.84 m.
In the case of the minimum radius or maximum superelevation, we use: (e+f)=v^2/127*R.
And in the case of the maximum radius or minimum super elevation, we use the design superelevation formula i.e. e=v^2 / 225*R.
In the case of the minimum radius or maximum superelevation, we use: (e+f)=v^2/127*R.
And in the case of the maximum radius or minimum super elevation, we use the design superelevation formula i.e. e=v^2 / 225*R.
(5)
Farouq algradi said:
12 months ago
Agree @Deepankar.
Rashmi said:
6 months ago
Design speed (kmph) : 30 40 50 60 70 80 90 100 110.
Radius in (meter): 40 70 100 150 200 260 320 400 440.
Radius in (meter): 40 70 100 150 200 260 320 400 440.
(4)
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