Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
40 comments Page 3 of 4.
Vijay said:
8 years ago
Here, R=v*v/g(e+f).
Suraj giri said:
8 years ago
R = 60*60/127(.07+.15) = 128.8.
RAHUL said:
8 years ago
What is 'F' and 'e'?
Roop said:
8 years ago
You are correct @Amrit.
Amrit said:
8 years ago
R min= V * V/127(e+F).
= 60 * 60/ 127(0.07+0.15),
= 128.8.
May be the correct answer 131m.
= 60 * 60/ 127(0.07+0.15),
= 128.8.
May be the correct answer 131m.
Varsha said:
8 years ago
0.07 for plain and rolling.
0.10 for the hilly area.
0.04 for urban roads and frequent intersections.
0.10 for the hilly area.
0.04 for urban roads and frequent intersections.
Manoj kabdwal said:
9 years ago
The e equals v*v/225R put e equation 0.07 find R.
It is 228.57 as this question is saying about design speed so above formula will be used.
It is 228.57 as this question is saying about design speed so above formula will be used.
Pramit said:
9 years ago
Here, the value of V^2/Rg should be under 0.25.
(1)
Johny Chauhan said:
9 years ago
V = √ 27.94 R.
Underroot of (27.94 multiply by 27.94)
Underroot of (27.94 multiply by 27.94)
Sahil Pathania said:
9 years ago
We can use the formula (e+f)=v^2/127R. As curve is horizontal take e=0.
R = 60 * 60/127(0.15) = 189 approx.
Ans is (D) none of these.
R = 60 * 60/127(0.15) = 189 approx.
Ans is (D) none of these.
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