Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
40 comments Page 2 of 4.
Mallesh said:
5 years ago
A 2-lane horizontal curve in which radius varies from infinite to some finite value R,
constructed in hilly terrain. The radius R of curve was equal to the absolute minimum radius. If the design speed and minimum speed on the curve is 60 kmph and 40 kmph respectively.
Then calculate the length of this horizontal curve.
constructed in hilly terrain. The radius R of curve was equal to the absolute minimum radius. If the design speed and minimum speed on the curve is 60 kmph and 40 kmph respectively.
Then calculate the length of this horizontal curve.
(1)
Sujeet said:
6 years ago
Absoulte min radius=( Vmin)^2/((127)(e(max)+.15).
Here Vmin=60, emax= .07 [7% for plain terrain].
=128.8m.
So, D is correct.
Here Vmin=60, emax= .07 [7% for plain terrain].
=128.8m.
So, D is correct.
Anomie said:
6 years ago
Thanks @Sahil Pathania.
Kinjal Patel said:
6 years ago
We can Also used,
R =v * v/0.22 * g.
= 128.89 Approx.
R =v * v/0.22 * g.
= 128.89 Approx.
Kalke patil said:
6 years ago
Thanks for the given information.
Bazid said:
6 years ago
For hilly road e = 0.10.
For plain e = 0.07 and the value of friction for cross slope f = 0.15.
For plain e = 0.07 and the value of friction for cross slope f = 0.15.
Tina said:
7 years ago
e= 0.07 & f= 0.15 (both are constant).
e + f= V^2/127R.
Where: R= radius of horizontal Curve.
R= 60^2/127(0.07+0.15).
R= 128.84m,
Note: here V is in kmph.
e + f= V^2/127R.
Where: R= radius of horizontal Curve.
R= 60^2/127(0.07+0.15).
R= 128.84m,
Note: here V is in kmph.
Muthu said:
7 years ago
How we can use e is 0.07 and f is 0.15?
Arsad Alam said:
7 years ago
Value of radius (R) =226m correct answer. So option (D) right.
Virender paul said:
7 years ago
Answer is in meter so we have to convert the speed in m/s.
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