Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
40 comments Page 2 of 4.
Muthu said:
7 years ago
How we can use e is 0.07 and f is 0.15?
Tina said:
7 years ago
e= 0.07 & f= 0.15 (both are constant).
e + f= V^2/127R.
Where: R= radius of horizontal Curve.
R= 60^2/127(0.07+0.15).
R= 128.84m,
Note: here V is in kmph.
e + f= V^2/127R.
Where: R= radius of horizontal Curve.
R= 60^2/127(0.07+0.15).
R= 128.84m,
Note: here V is in kmph.
Bazid said:
6 years ago
For hilly road e = 0.10.
For plain e = 0.07 and the value of friction for cross slope f = 0.15.
For plain e = 0.07 and the value of friction for cross slope f = 0.15.
Kalke patil said:
6 years ago
Thanks for the given information.
Kinjal Patel said:
6 years ago
We can Also used,
R =v * v/0.22 * g.
= 128.89 Approx.
R =v * v/0.22 * g.
= 128.89 Approx.
Anomie said:
6 years ago
Thanks @Sahil Pathania.
Sujeet said:
6 years ago
Absoulte min radius=( Vmin)^2/((127)(e(max)+.15).
Here Vmin=60, emax= .07 [7% for plain terrain].
=128.8m.
So, D is correct.
Here Vmin=60, emax= .07 [7% for plain terrain].
=128.8m.
So, D is correct.
Shyamlal said:
5 years ago
Equation for super Elevation:
e+f=v*v/225R(design speed),
So R=v*v/225(e+f),
Take e=0.07 & f=0.15,
R=60*60/225(0.07+0.15),
It get R=72.72m.
So the answer is option D.
ie =60*60/225.
e+f=v*v/225R(design speed),
So R=v*v/225(e+f),
Take e=0.07 & f=0.15,
R=60*60/225(0.07+0.15),
It get R=72.72m.
So the answer is option D.
ie =60*60/225.
Sugumar said:
5 years ago
How can we guess the weather it is a mixed traffic or single traffic. Can anyone explain based on this question?
Rafeek said:
5 years ago
Option D None of above.
The compensate gradients is 4 degree for, so the radius will be 60 x 4 = 120m.
The compensate gradients is 4 degree for, so the radius will be 60 x 4 = 120m.
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