Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
40 comments Page 4 of 4.
Snehal said:
9 years ago
You cannot use (e + f) = v^2/127R. It is for super-elevated curves not for horizontal curves.
Gurdeep singh said:
1 decade ago
R = 60*60/127(.07+.15) = 128.8.
Johny Chauhan said:
9 years ago
V = √ 27.94 R.
Underroot of (27.94 multiply by 27.94)
Underroot of (27.94 multiply by 27.94)
Manoj kabdwal said:
9 years ago
The e equals v*v/225R put e equation 0.07 find R.
It is 228.57 as this question is saying about design speed so above formula will be used.
It is 228.57 as this question is saying about design speed so above formula will be used.
Varsha said:
8 years ago
0.07 for plain and rolling.
0.10 for the hilly area.
0.04 for urban roads and frequent intersections.
0.10 for the hilly area.
0.04 for urban roads and frequent intersections.
Amrit said:
8 years ago
R min= V * V/127(e+F).
= 60 * 60/ 127(0.07+0.15),
= 128.8.
May be the correct answer 131m.
= 60 * 60/ 127(0.07+0.15),
= 128.8.
May be the correct answer 131m.
Roop said:
8 years ago
You are correct @Amrit.
RAHUL said:
8 years ago
What is 'F' and 'e'?
Suraj giri said:
8 years ago
R = 60*60/127(.07+.15) = 128.8.
Vijay said:
8 years ago
Here, R=v*v/g(e+f).
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