Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 5 (Q.No. 36)
36.
In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is
Discussion:
16 comments Page 2 of 2.
Binny bana said:
5 years ago
A is correct.
Breaking distance =v^2/2gf.
8=10^2/2*9.81*f,
so = 100/156.7.
=.64 answer.
Breaking distance =v^2/2gf.
8=10^2/2*9.81*f,
so = 100/156.7.
=.64 answer.
(6)
Sudhanshu said:
4 years ago
@Shubham.
It's given breaking distance, not SSD.
Braking dist:V^2/254f.
It's given breaking distance, not SSD.
Braking dist:V^2/254f.
(5)
Nabin Adhikari said:
1 decade ago
F = V^2/(254S) = 0.64.
So correct answer might be A.
So correct answer might be A.
(1)
Sourish said:
7 years ago
What about none of this? 16 also more than .15.
Roy said:
8 years ago
The correct Answer is A.
Koushal said:
5 years ago
Here f= a/g.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers