Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 5 (Q.No. 36)
36.
In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is
Discussion:
16 comments Page 1 of 2.
Nabin Adhikari said:
1 decade ago
F = V^2/(254S) = 0.64.
So correct answer might be A.
So correct answer might be A.
(1)
ARUN KUMAR said:
9 years ago
f' = V*2 / 2gL
= (36/3.6)**2/ 2 * 9.81 * 8.0 v = V /3.6
= 36/3.6
= 10m/sec
= 0.64m (say)
= (36/3.6)**2/ 2 * 9.81 * 8.0 v = V /3.6
= 36/3.6
= 10m/sec
= 0.64m (say)
(1)
Roy said:
8 years ago
The correct Answer is A.
Gubendhiran said:
8 years ago
SSD=lag distance + braking distance.
SSD=Vt +[(V^2)÷(2g(f+-g))],
Breaking distance=(v^2)÷(254f+-g),
We don't have gradients so leave it.
8=(36^2)÷(254f),
f=0.63779=0.64,
So option A is correct.
SSD=Vt +[(V^2)÷(2g(f+-g))],
Breaking distance=(v^2)÷(254f+-g),
We don't have gradients so leave it.
8=(36^2)÷(254f),
f=0.63779=0.64,
So option A is correct.
(1)
Kshitiz said:
8 years ago
Friction coefficient value never exceed 0.4
Longitudinal friction coefficient range 0.3 to o.4
Lateral friction coefficient value generally 0.15
You can use the formula for finding friction coefficient but it exceeds limiting value. So Ans is 0.16 correct ie it took lateral friction value.
Longitudinal friction coefficient range 0.3 to o.4
Lateral friction coefficient value generally 0.15
You can use the formula for finding friction coefficient but it exceeds limiting value. So Ans is 0.16 correct ie it took lateral friction value.
Raj said:
8 years ago
Yes, absolutely correct @Kshitiz.
The Limiting value is 0.4. The correct option A is correct.
The Limiting value is 0.4. The correct option A is correct.
Sourish said:
8 years ago
What about none of this? 16 also more than .15.
Suman said:
7 years ago
It seems to be option D is correct as 'f' in the breaking distance formula signify longitudinal friction, which varies from 0.4 to 0.35 depending on the speed, while the lateral friction 'f' comes to design the superelevation instead. So option D be the correct answer.
(1)
Akhila said:
6 years ago
Yes, in sight distance its always Longitudinal friction not lateral. So, Option D as it exceeds the range (0.35-0.40).
Koushal said:
6 years ago
Here f= a/g.
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