Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 2 (Q.No. 3)
3.
According to IRC : 52-1973, for a single lane National Highway in hilly region,
Discussion:
11 comments Page 1 of 2.
Asoke said:
1 year ago
The total width of the carriageway for a single lane is 3.75 (NH/SH), Minimum shoulder to be provided is 1.25 on each side.
Thus total width will be ( 2S+carriage way)={(2×1.25)+3.75} = 6.25m.
Hence, D is the correct answer.
Thus total width will be ( 2S+carriage way)={(2×1.25)+3.75} = 6.25m.
Hence, D is the correct answer.
(1)
Navab said:
4 years ago
As per IRC:
The total width of carriage way for single lane is 3.75 (NH/SH), for two-lane its 7.0, for multi-lane its 3.50/lane.
For MDR /ODR : 3.50, for two LANE 5.5,
for VR: 3.0.
So, option A is correct.
The total width of carriage way for single lane is 3.75 (NH/SH), for two-lane its 7.0, for multi-lane its 3.50/lane.
For MDR /ODR : 3.50, for two LANE 5.5,
for VR: 3.0.
So, option A is correct.
(2)
Olau said:
6 years ago
Answer D is correct. I agree with the given answer.
Aadarsh said:
7 years ago
For plane 7.9m (3.6+3.6+ 0.7) is 7.9.
For hills 6.25m (3.75+3.75+1.25).
For hills 6.25m (3.75+3.75+1.25).
Ramya said:
7 years ago
Which is the correct option? Please explain me.
Abhi said:
7 years ago
IRC suggested as the roadway width for mountainous and steep terrain for NH single lane road is 6.25.
So, ans C is correct.
So, ans C is correct.
Andal said:
8 years ago
Option D is correct.
In Mountainous and Steep terrain the total width of Road way or Formation width = 3.75 ( for plain terrain ) + both sides shoulders of 1.25m = 3.75 + 2*1.25 = 6.25m.
In Mountainous and Steep terrain the total width of Road way or Formation width = 3.75 ( for plain terrain ) + both sides shoulders of 1.25m = 3.75 + 2*1.25 = 6.25m.
Apoorc said:
8 years ago
I think its 12 mtr Recommend by Irc For NH.
GOPINATH said:
8 years ago
I think the answer is only A.
Ekpe omini said:
9 years ago
Then what is the total width?
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