Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 3 (Q.No. 37)
37.
Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is
80 m
100 m
120 m
150 m
200 m
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Mx.com said:   3 years ago
Nice answer, Thanks all for explaining.
(1)

Sanjay said:   5 years ago
What is the overtaking sight distance at a different speed? Can anyone explain me?
(2)

Achumi kits said:   5 years ago
Thanks @Raman.

Vineela said:   6 years ago
SSD = LD+BD.
Vtr + v^2/2gf.
(80x0.278)*2.5+(80x0.278)^2/2x9.81x0.35.
=127m ~ 120m.
(2)

R. Nath said:   6 years ago
V= 80km/hr.
Convert it to m/s.
That is, 80(1000/3600) = 22.22m/sec.

f = 0.35.
t = 2.5 sec.

SsD = (v.t) +((v^2)/(2.g.f)).
= put values.
= 127m.
(1)

Subhasmita patra said:   6 years ago
How v= 22.23?

Please explain it.

Karthi said:   7 years ago
@Harsh Shukla.

We can take f= 0.35 to 0.4 directly.

Because f -coefficient of longitudinal friction.

Harsh Shukla said:   7 years ago
Stopping distance = vt+[v^2/(2*f*g)].

v= velocity , t= reaction time.
v=22.23 m/s , t= 2.5sec (given by IRC), g=9.81 m/s^2.
f=braking efficiency * f(actual).

Braking efficiency is considered 50% if not given.
f(actual) is considered 0.7 if not given approximately.
This gives f=(0.5*0.7)=0.35.
Stopping distance = (22.23*2.5)+[((22.23)^2)/(2*0.35*9.81)] = 127 m ~ 120m (approx).
(2)

Raman said:   7 years ago
20kmph---20m.
25kmph---25m.
30kmph---30m.
40kmph---45m.
50kmph---60m.
60kmph---80m.
65kmph---90m.
80kmph---120m.
100kmph---180m.
(6)

Binod nath said:   8 years ago
It's 180 m for design speed of 100 kmph.


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