Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
56 comments Page 3 of 6.
SANTOSH kumar said:
7 years ago
e=V2/gr.
So, I think all option is true. But, e is directly proportional to the square of the velocity of the vehicle.
So, I think all option is true. But, e is directly proportional to the square of the velocity of the vehicle.
Bikash Kabiraj said:
8 years ago
V^2/gr.
v-velocity of the vehicle,
g-gravitational force,
r-radius of the curve so right answer is option A.
v-velocity of the vehicle,
g-gravitational force,
r-radius of the curve so right answer is option A.
Bcr said:
1 decade ago
e+f=(v*v)/gR
So directly prop to v.
Indirectly prop to radius and gravity.
Hence option A would be the answer.
So directly prop to v.
Indirectly prop to radius and gravity.
Hence option A would be the answer.
Joce said:
1 decade ago
It is directly proportional to the velocity square and inversely proportional to the radius of curvature.
Lucky jaswal said:
9 years ago
directly proportional to velocity and width.
Inversely to the radius.
It seems wrong in acceleration.
Inversely to the radius.
It seems wrong in acceleration.
Snehal said:
9 years ago
e is the rate of superelevation.
h = e * B is the super elevation (which is proportional to width).
h = e * B is the super elevation (which is proportional to width).
Pratibha Nishad said:
7 years ago
Directly proportional to the velocity and also inversely proportional to the radius of curvature.
(1)
Priya said:
1 decade ago
Directly proportional to the velocity and also inversely proportional to the radius of curvature.
Pari.. said:
6 years ago
Super elevation is inversely proportional to the radius.
E!=e B where e is the super-elevation.
E!=e B where e is the super-elevation.
Lechi konyak said:
3 years ago
Superelevation is directly proportional to the velocity of the vehicle. So, Option A is correct.
(1)
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