Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 12)
12.
Pick up the incorrect statement from the following. The super-elevation on roads is
Discussion:
56 comments Page 2 of 6.
Swar said:
7 years ago
e=tan (θ) = opp/adj = h/b = central rise/width.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
So super elevation is inversely proportional to width of pavement. But they have given as directly prop. So the answer is A.
SABIN ACHARYA said:
8 years ago
E=eB.
e=v*v/gR.
SO,
E=v*v*B/gR.
From final equation.
E directly proportion to width, square of velocity and,
inversely proportional to the g and R.
SO, ans B IS RIGHT.
e=v*v/gR.
SO,
E=v*v*B/gR.
From final equation.
E directly proportion to width, square of velocity and,
inversely proportional to the g and R.
SO, ans B IS RIGHT.
Dr. ANUJ said:
4 years ago
For the total amount of superelevation, A, C, and D are correct.
So, incorrect can only be B as it is proportional to the square of the speed and not the speed only.
So, incorrect can only be B as it is proportional to the square of the speed and not the speed only.
(1)
Bharathi said:
1 decade ago
Super elevation is directly proportional to the square of the velocity and inversely proportional to the acceleration due to gravity, radius of the curvature.
Subeer kumar said:
9 years ago
Superelevation is directly proportional to velocity of the vehicle because for particular curve on the road radius of curve remains constant for that curve.
Srikanth IIITBasar said:
1 decade ago
Actually it is not directly proportional to width of pavement. Because,
Superelevation (e) = tan (tita) = sin (tita) = opp side /hyp= E/ width of pavement.
Superelevation (e) = tan (tita) = sin (tita) = opp side /hyp= E/ width of pavement.
Pakeeza Jhan said:
9 years ago
Super-elevation = v^2/2r.
Hence, it should be directly proportional to square root of velocity and inversely proportional to the radius of curvature.
Hence, it should be directly proportional to square root of velocity and inversely proportional to the radius of curvature.
JP Mahanta said:
6 years ago
Super elevation doesn't depends on road width, The E value (height of outer edge of road at super-elevation) depends upon e (rate of super-elevation).
Engr asad said:
8 years ago
W V^2
_____
gr
Directly proportional = width and sq of speed (not velocity).
Inversely = acceleration due to gravity and radius of the curve.
_____
gr
Directly proportional = width and sq of speed (not velocity).
Inversely = acceleration due to gravity and radius of the curve.
TANMOY SAHA said:
1 decade ago
Superelevation(E) = Rate of superelevation(e)* Width of pavement(B).
So E directly proportional to B,
So the correct option will be 'B' .
So E directly proportional to B,
So the correct option will be 'B' .
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