Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 6)
6.
The focal length of the object glass of a tacheometer is 200 mm, the distance between the vertical axis of the tachometer and the optical centre of the object glass is 100 mm and the spacing between the upper and lower line of the diaphragm axis is 4 mm. With the line of collima-tion perfectly horizontal, the staff intercepts are 1 m (top), 2 m (middle), and 3 m (bottom). The horizontal distance (m) between the staff and the instrument station is
Discussion:
7 comments Page 1 of 1.
Pulkit said:
9 years ago
D = (f/i) * s + (f + d)~ ks + c.
f = 200, s = intercept = 3 - 1 = 2, i = 4, d = 100.
Hence after calculation 100.3.
f = 200, s = intercept = 3 - 1 = 2, i = 4, d = 100.
Hence after calculation 100.3.
Bala said:
9 years ago
How it comes, can you please clarify it?
Rakesh kumar said:
9 years ago
Can anyone explain the solution with the correct substitution?
Unknown said:
8 years ago
f = 200mm.
d = 100mm.
i = 4mm.
S=(3-1)=2m.
D= KS +C.
K= f/i.
= 200/4.
= 50.
C = f+d.
= 200+100.
= 300mm.
D = 50 x2m + 0.300m.
= 100.3m.
d = 100mm.
i = 4mm.
S=(3-1)=2m.
D= KS +C.
K= f/i.
= 200/4.
= 50.
C = f+d.
= 200+100.
= 300mm.
D = 50 x2m + 0.300m.
= 100.3m.
Ajaz Ahmed said:
8 years ago
Distance= KS+C.
K=f/i
f= 200
I= 4
Then k= 200/4
K= 50
S= lower cross hair - upper cross hair
= 3-1
= 2
C= focal length+optical center of glass
200+100
=300
C= 0.3
i.e
50x2 + 0.3
100.3.
K=f/i
f= 200
I= 4
Then k= 200/4
K= 50
S= lower cross hair - upper cross hair
= 3-1
= 2
C= focal length+optical center of glass
200+100
=300
C= 0.3
i.e
50x2 + 0.3
100.3.
(4)
Nikunj said:
8 years ago
From Where do i = 4 come?
Yash said:
5 years ago
Thanks all.
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