Discussion :: GATE Exam Questions - Section 1 (Q.No.35)
|Samala Laxman said: (Dec 17, 2013)|
|G = sqrt(power input/volume*dynamic viscosity).
G = 900/sec.
Q = 28800m^3/day = 0.33m^3/sec.
t = 2 min = 120 sec.
Volume = Q*t= 40m^3.
Dynamic viscosity = kinematic viscosity/density.
If we substitute all these values in above formula we will get power = 32400W.
|Kirubakara Raj said: (Aug 16, 2016)|
|Thanks for your explanation @Samala.|
|Ruchitamalunjkar said: (Feb 6, 2019)|
|Please explain the answer briefly.|
|Huidrom said: (Jun 28, 2019)|
|Dynamic viscosity = kinematic viscosity * Density.|
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