Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 40)
40.
A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of 200 kN/m2. The specimen failed at a shear stress of 100 kN/m2. The angle of internal friction of the soil (degrees) is
Discussion:
4 comments Page 1 of 1.
SAMALA LAXMAN said:
1 decade ago
Shear stress = C + normal stress*tan (theta).
Here given C=0, shear stress = 100 and normal stress = 200.
After putting all these values in above formula we will get.
"theta= 26.56".
Here given C=0, shear stress = 100 and normal stress = 200.
After putting all these values in above formula we will get.
"theta= 26.56".
Apurva said:
7 years ago
c = 6tθ.
6 = shear stress.
t - tan.
c - coulmn constant.
6 = shear stress.
t - tan.
c - coulmn constant.
NITIN MANE said:
3 years ago
@Samala.
What is 26.55"? please explain me the answer.
What is 26.55"? please explain me the answer.
Nagendra kumar said:
5 years ago
s = c + normal stress * tan θ.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers