Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 49)
49.
The members EJ and IJ of steel truss shown in the figure below are subjected to a temperature rise of 30° C. The coefficient of thermal expansion of steel is 0.000012 per °C per unit length. The displacement (mm) of joint E relative to joint H along the direction HE of the truss, is
Discussion:
5 comments Page 1 of 1.
Sathya said:
10 years ago
How it will come?
Revathi said:
9 years ago
What is the formula?
A- HIDAR said:
8 years ago
Stresses due to thermal expansion = Esteel *α * T = 2.10*10^5 * 0.000012 * 30 = 75.6 Mpa.
Displacement between two point E, H is diagonal JG which has length = 4.24 m.
Displacement = F*L/AE = stresses * (L/E) = 75.60 MPA * 4240 / 2.1 * 10^5 = 1.5264 mm in Diagonal which expansion tow joint E,H 1.52/2 = 0.763 mm.
Displacement between two point E, H is diagonal JG which has length = 4.24 m.
Displacement = F*L/AE = stresses * (L/E) = 75.60 MPA * 4240 / 2.1 * 10^5 = 1.5264 mm in Diagonal which expansion tow joint E,H 1.52/2 = 0.763 mm.
ABC said:
7 years ago
@Hidar.
Can you please explain why expansion at E, H is taken as half?
Can you please explain why expansion at E, H is taken as half?
Nikhil said:
2 years ago
Can you explain the concept of relative displacement? Please explain me.
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