Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 16)
16.
Water flows at a depth of 0.1 m with a velocity of 6 m/s in a rectangular channel. The alternate dpeth is
Discussion:
11 comments Page 1 of 2.
Krishan Hatria said:
4 years ago
In Question, if asked conjugate depth instead of alternate depth then the answer is 0.81m.
(3)
Mayuri jamdade said:
5 years ago
Y2 = 1/2 * Y1 * (((1+(8 * Fr^2))^0.5)-1).
Fr = (V/((gY1)^0.5)) = (6/((9.81*0.1)^0.5)) = 6.06
Y2 = 0.5 * 0.1*(((1+(8 * 6.06 * 6.06))^0.5)-1) = 0.808m
Y2 = 0.808m is approximately 0.81m.
Fr = (V/((gY1)^0.5)) = (6/((9.81*0.1)^0.5)) = 6.06
Y2 = 0.5 * 0.1*(((1+(8 * 6.06 * 6.06))^0.5)-1) = 0.808m
Y2 = 0.808m is approximately 0.81m.
(2)
Krishan Hatria said:
4 years ago
@All.
According to me the solution is
q=v*y1 = 0.1*6 = .6 cubic meter per meter width.
Now use formula drive from equating specific energy at 1-1 section and 2-2 section.
q^2÷ 2g = y1^2 y2^2 ÷ (y one + y two) after solving y two= 1.93m.
Correct me if I am wrong.
According to me the solution is
q=v*y1 = 0.1*6 = .6 cubic meter per meter width.
Now use formula drive from equating specific energy at 1-1 section and 2-2 section.
q^2÷ 2g = y1^2 y2^2 ÷ (y one + y two) after solving y two= 1.93m.
Correct me if I am wrong.
(2)
Shaheen said:
1 decade ago
y2/y1 = 1/2[-1+sqrt(1+8Fr2)].
Hamza said:
7 years ago
The answer is "A" because on equating the equations E=Y+ (V)2/2g as a first equation and E=Y+(q/y)2/2g we get nearly .32.
Neeraj nautiyal said:
7 years ago
Can anyone please explain this?
Basith said:
7 years ago
0.1/2*(√(1+8*Fr^2)-1) = 0.808.
fr = 6/√(9.81*0.1).
fr = 6/√(9.81*0.1).
Keshav Kaushik said:
7 years ago
Fr = V/√(gL) = 6.
y2 = y1* 0.5* [ -1+ √( 1+8*Fr^2)].
y2 = 0.8 is the answer.
y2 = y1* 0.5* [ -1+ √( 1+8*Fr^2)].
y2 = 0.8 is the answer.
Anomiee said:
7 years ago
Here it is asking about alternate depth not sequent depth. For alternate depths, we have to equate specific energies at the two sections.
Replyfast said:
6 years ago
Can anyone explain how to calculate alternate depth for this numerical problem?
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