Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 35)
35.
In a drained triaixal compression test, a saturated specimen of a cohesionless sand fails under a deviatoric stress of 3 kgf/cm2 when the cell pressure is 1 kgf/cm2 . The effective angle of shearing resistance of sand is about
Discussion:
3 comments Page 1 of 1.
Suraj Saqib said:
2 weeks ago
σ1 = 3 + 1 = 4.
σ2 = 1.
sin φ = (σ1 - σ2)/(σ1 + σ2).
φ = sin-1( 4-1 )/(4+1),
= sin-1 (3/5).
= 36.87 i.e (37).
σ2 = 1.
sin φ = (σ1 - σ2)/(σ1 + σ2).
φ = sin-1( 4-1 )/(4+1),
= sin-1 (3/5).
= 36.87 i.e (37).
Srilu said:
1 decade ago
Deviated stress = 3 kgf/cm^2, cell pressure=1 kgf/cm^2.
Effective stress = d.s+c.p,
Then eff.stress = 4.
We have an equation at plastic equibilibrium.
Eff.stress=cell pressure x tan^2(x)+2c x tan(x),
For sand(cohesionless), c=0,
Eff.str = c.p x tan^2(x).
4 = 1*tan^2(x), x = tan^-1(4/2) = 63.43,
We known that x = 45+(frin.ang)/2,
Then fri.angle = (63.43-45)*2 = 36.8.
Effective stress = d.s+c.p,
Then eff.stress = 4.
We have an equation at plastic equibilibrium.
Eff.stress=cell pressure x tan^2(x)+2c x tan(x),
For sand(cohesionless), c=0,
Eff.str = c.p x tan^2(x).
4 = 1*tan^2(x), x = tan^-1(4/2) = 63.43,
We known that x = 45+(frin.ang)/2,
Then fri.angle = (63.43-45)*2 = 36.8.
Iswarya said:
1 decade ago
Can anyone explain the detailed solution for this?
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