Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 1 (Q.No. 5)
5.
In a steady radial flow into an intake, the velocity is found to vary as (1/r2), where r is the radial distance. The acceleration of the flow is proportional to
Discussion:
27 comments Page 2 of 3.
Madhu kumar said:
9 years ago
I agree with your answer @Aparna.
NATHAN said:
9 years ago
What condition to apply r/2 in V in the question?
Please anyone tell me.
Please anyone tell me.
Tulasi sivaprasad said:
9 years ago
Please explain clearly.
Kumari juhi said:
9 years ago
a = V2/r = (1/r2)2/r = 1/r5.
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Vishal babu jaiswal said:
8 years ago
For radial flow : a =v2/r.
V=k/r2, hence put the value in above equation, then a = k2/r5.
V=k/r2, hence put the value in above equation, then a = k2/r5.
DEEPANCHAKARAVARTHY said:
8 years ago
Thanks @Aparna.
Maha said:
8 years ago
For radial flow,
a = V^2/r.
Here, V = 1/r^2 hence,
a = [(1/r^2)^2]/r,
= (1/r^4)/r,
a = 1/r^5.
a = V^2/r.
Here, V = 1/r^2 hence,
a = [(1/r^2)^2]/r,
= (1/r^4)/r,
a = 1/r^5.
Swapan said:
8 years ago
Acceleration a= v2/r--- eq-01
Given velocity v=1/r2,
putting the value v in eq-. no 01,
therefore,a = v.v/r= ((1/r2).(1/r2))/r =(1/r4)/r = 1/r4 x 1/r = 1/r5.
Given velocity v=1/r2,
putting the value v in eq-. no 01,
therefore,a = v.v/r= ((1/r2).(1/r2))/r =(1/r4)/r = 1/r4 x 1/r = 1/r5.
M.naresh said:
8 years ago
We know the radial acc is=V2/r .(1/(r2)2*r=1/r5.
Niki said:
8 years ago
I agree @Maha.
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