### Discussion :: GATE Exam Questions - Section 1 (Q.No.17)

Desinerd said: (Aug 4, 2014) | |

Cu->Shear strength parameter 70 KN/m2. The formula to be used is : F.S = Cu/Ns*Gamma symbol*H. Where, F.S = factor of safety. Cu=read as C sub u = Undrained shear strength parameter = 70KN/m2. Gamma Symbol = γ = unit weight of saturated clay = 20 KN/m3. H = Depth/Height = 10m. Ns = read as N sub s = Taylor's stability Co-efficient = 0.18. F.S thus works out to be = 1.94444,which approx ~ 2. |

Vls said: (Apr 26, 2016) | |

This can also be calculated by the graph. |

Rihaan said: (Aug 25, 2016) | |

Which formula is applied here? |

Karthik said: (Sep 12, 2016) | |

F.S = Cu/Ns * γ * H. = 70 * 20 * 10/(0.18 * 40 * 100). = 1.94. |

Prosanta Bittel said: (Feb 8, 2017) | |

According to me, F.S = Cu/(Ns * γ * H). = 2.08. |

Asaithambi said: (Feb 9, 2017) | |

Shear strength parameters are cu = 70 kN/m2, Saturated clay of unit weight = 20 kN/.m3, Coefficient for φu = 0.18, Excavated to a depth =10m, Factor of safety=(Cu/(coefficient*h*unit weight). = (70/(0.18*10*20). = 2. |

Jeganathan said: (Feb 1, 2020) | |

Stability number sn = c/(FrH). |

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