Discussion :: GATE Exam Questions - Section 1 (Q.No.17)
|Desinerd said: (Aug 4, 2014)|
|Cu->Shear strength parameter 70 KN/m2.
The formula to be used is : F.S = Cu/Ns*Gamma symbol*H.
F.S = factor of safety.
Cu=read as C sub u = Undrained shear strength parameter = 70KN/m2.
Gamma Symbol = γ = unit weight of saturated clay = 20 KN/m3.
H = Depth/Height = 10m.
Ns = read as N sub s = Taylor's stability Co-efficient = 0.18.
F.S thus works out to be = 1.94444,which approx ~ 2.
|Vls said: (Apr 26, 2016)|
|This can also be calculated by the graph.|
|Rihaan said: (Aug 25, 2016)|
|Which formula is applied here?|
|Karthik said: (Sep 12, 2016)|
|F.S = Cu/Ns * γ * H.
= 70 * 20 * 10/(0.18 * 40 * 100).
|Prosanta Bittel said: (Feb 8, 2017)|
|According to me,
F.S = Cu/(Ns * γ * H).
|Asaithambi said: (Feb 9, 2017)|
|Shear strength parameters are cu = 70 kN/m2,
Saturated clay of unit weight = 20 kN/.m3,
Coefficient for φu = 0.18,
Excavated to a depth =10m,
Factor of safety=(Cu/(coefficient*h*unit weight).
|Jeganathan said: (Feb 1, 2020)|
|Stability number sn = c/(FrH).|
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.