Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 50)
50.
A-2-hour unit hydrograph can be approximated as trapezoidal as shown in the below figure. The unit hydrograph refers to catchment of area
Discussion:
9 comments Page 1 of 1.
Ankit said:
1 decade ago
If peak discharge is taken as 24m3 means Qp=24m3.
And area of trapezium is h/2(a+b) means=Qp/2(a+b)x60x60=Area x 10^4 by solving this we are getting 138.24km^2.
Just help me out how would you get the catchment as 384 km^2
And area of trapezium is h/2(a+b) means=Qp/2(a+b)x60x60=Area x 10^4 by solving this we are getting 138.24km^2.
Just help me out how would you get the catchment as 384 km^2
Jyothi said:
10 years ago
Volume of the catchment = A*(1/100).
= 1/2*(28+4)*3600*24 = A*(1/100).
A = 138.24*10^6 m^2.
A = 138.24 km^2.
= 1/2*(28+4)*3600*24 = A*(1/100).
A = 138.24*10^6 m^2.
A = 138.24 km^2.
Vaibhav said:
9 years ago
@Jyothi, @Ankit.
Actually, you both find the area in km2 and in answer area is given in m2.
How? explain.
Actually, you both find the area in km2 and in answer area is given in m2.
How? explain.
Asaithambi said:
9 years ago
Trapezium area = ((a+b)/2)*h.
a = 4
b = 28
h = 24.
a = 4
b = 28
h = 24.
Bh@nu said:
8 years ago
Trapezoid area=1/2*(a+b)*h.
A = 0.5 * (4+28) * 24 = 384 m^2.
A = 0.5 * (4+28) * 24 = 384 m^2.
Dinesh said:
8 years ago
B is the right one Area = volume of unit hydrograph/depth.
Depth =1cm so1/100.
Depth =1cm so1/100.
Tapu said:
7 years ago
Trapezoidal area = 1/2 (a+b)*h m^2
= 1/2 (4+28)*24 m^2,
= 384m^2.
= 1/2 (4+28)*24 m^2,
= 384m^2.
Ranjan said:
7 years ago
Area under curve/depth (1 cm).
HARSH RAJ said:
3 years ago
The volume of catchment = A * 1/100.
1/2 (4+28) * 24 * 3600 = A/100.
A = 138240000 M^2.
A = 138.24 KM^2.
1/2 (4+28) * 24 * 3600 = A/100.
A = 138240000 M^2.
A = 138.24 KM^2.
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