Discussion :: GATE Exam Questions - Section 1 (Q.No.30)
|Praveen said: (Jun 17, 2015)|
|It should be steep slope because critical gradient is more than given depth hence its B only.|
|Dhawal said: (Jul 18, 2015)|
|Answer should be steep, as by calculations, critical depth = 0.46 m; whereas given normal depth is 0.25 m, as critical depth>normal depth so it would be steep.|
|Amaresh Dhibar said: (Nov 4, 2015)|
|How the calculation made 0.46?|
|Shail said: (Dec 12, 2015)|
|Yes @Dhawal, you guys are right it is Steep yc = 0.46 and yn = 1.|
|Siva said: (Aug 19, 2016)|
|Yeah, you guys are right, I agree with the option B.|
|Bala said: (Dec 25, 2016)|
|How 0.46 could came?|
|Bhawna said: (Jan 26, 2017)|
|yc = (q2/g)1/3 = 0.46.
Option B is correct because 0.25less than 0.46, critical depth is more means steep slope.
|Manprit said: (Mar 1, 2017)|
|Answer B is correct.(q2/g)^1/3 = 0.46, which is greater than 0.25.|
|Anuskha Sharma said: (Nov 22, 2017)|
|Can anyone please elaborate me?|
|Sky said: (Feb 3, 2018)|
|Yn= 1 & Yc = (q^2÷g)^1÷3.
It is adverse slope.
|Preetam Tomar said: (Feb 5, 2018)|
|Steep is the correct answer.|
|Abc said: (Apr 5, 2018)|
|Yes steep should be the correct answer as critical depth is higher than normal depth.
Type of slope ----- Relation
Mild ----- Yn>Yc
Steep ----- Yn<Yc
critical ----- Yn=Yc
Adverse ----- Slope<0
Horizontal ----- Slope=0.
Where Yn & Yc are normal and critical depth.
|Bhutan said: (Aug 31, 2019)|
|It should be Steep.|
|Sadashiva said: (Sep 15, 2019)|
|Yc = ((q^2/g))^(1/3) q=Q/B, q=1/1=1.
Yc = ((1 /9.81))^(1/3).
Yc = 0.467m.
Given Yn = 250mm = 0.25m.
Condition when, yc>yn(steep slope).
So, the answer is option B.
|Nayab said: (Sep 24, 2020)|
|Calculate the slope of bed if it's less than zero it's adverse.|
|Kshitij said: (Sep 25, 2020)|
|How to calculate the bed slope? Please explain.|
|Dixita said: (Oct 23, 2020)|
|How to find yn when S is not known? 0.25m is not yn, right? Anyone, please explain in detail.|
|Bisy said: (Dec 23, 2020)|
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