Civil Engineering - Estimating and Costing - Discussion
Discussion Forum : Estimating and Costing - Section 1 (Q.No. 19)
19.
The expected out turn of cement concrete 1 : 2 : 4 per mason per day is
Discussion:
24 comments Page 2 of 3.
Abhisek roy said:
9 years ago
How to calculate it? please explain.
Sundar said:
8 years ago
Anyone please explain it clearly.
MALAY DEY said:
8 years ago
How it is calculated? Please explain in detail.
(1)
Pandiyarajan said:
8 years ago
Please give the answer & explain it.
The expected out turn of cement concrete 1 : 1.5 : 3 per mason per day is?
The expected out turn of cement concrete 1 : 1.5 : 3 per mason per day is?
Nadee said:
8 years ago
1 : 2 : 4 concrete, 1m3 need Labour constant.
Mixing concrete --------> 3.00 hour/m3.
Lifting and carrying concrete --------> 1.20 hour/m3.
c.compacting concrete --------> 0.80 hour/m3.
d.leveling surface of concrete --------> 0.10 hour/m3.
Total=(3+1.2+0.8+0.1) = 5.
Mixing concrete --------> 3.00 hour/m3.
Lifting and carrying concrete --------> 1.20 hour/m3.
c.compacting concrete --------> 0.80 hour/m3.
d.leveling surface of concrete --------> 0.10 hour/m3.
Total=(3+1.2+0.8+0.1) = 5.
H.J said:
8 years ago
1 : 1.5 : 3 material and grade is different. But labour constant is same. So, the answer 5.
(3)
King said:
8 years ago
1:2:4 it means M15 grade it means work in foundation which 5m^3 per mason per day.
Naven said:
7 years ago
100 M3 for 13 masons.
Per one mason =100/13=7.69m3 dry concrete,
Dry concrete= 1.52*wet concrete,
So wet = 7.69/1.52= 5 m3.
Per one mason =100/13=7.69m3 dry concrete,
Dry concrete= 1.52*wet concrete,
So wet = 7.69/1.52= 5 m3.
(3)
Sunnyod said:
6 years ago
Explain it.
Arun Prasad said:
6 years ago
For 10 m3 of cement concrete work.
Masons needed are 2.
Hence there is one mason, then the quantity in m3 is 5m3.
Masons needed are 2.
Hence there is one mason, then the quantity in m3 is 5m3.
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