Civil Engineering - Estimating and Costing - Discussion
Discussion Forum : Estimating and Costing - Section 1 (Q.No. 41)
41.
The total length of a cranked bar through a distance (d) at 45° in case of a beam of effective length L, is
Discussion:
8 comments Page 1 of 1.
Himangshu Saikia said:
2 months ago
30° = 0.27d.
45° = 0.42d.
60° = 0.57d.
90° = 0.89d.
45° = 0.42d.
60° = 0.57d.
90° = 0.89d.
Vishnu said:
7 months ago
Here in this question, it is mentioned in the case of BEAM.
So, cranked must be on both sides.
The total length of the cranked bar = L + 2 * 0.42d.
So, cranked must be on both sides.
The total length of the cranked bar = L + 2 * 0.42d.
Arun said:
5 years ago
Option A is correct because it is not mentioned about the crank on both sides.
(1)
Danish said:
5 years ago
Here it is not mentioned that crank is on both sides. So the answer must be A.
Crank is provided to resist negative BM.
Crank is provided to resist shear force.
Crank is provided to resist negative BM.
Crank is provided to resist shear force.
Sachin s Naik said:
6 years ago
If bar cranked at 30 then extra length will be 2*0.27d.
Mohd Asif khan said:
6 years ago
Length of crank bar on one side= d/sin@ - d/tan@
= d/sin45° - d/tan45°
=0.42d.
Therefor total length of cranked bar on both sides = (L+2x0.42d).
= d/sin45° - d/tan45°
=0.42d.
Therefor total length of cranked bar on both sides = (L+2x0.42d).
(5)
Anjali said:
6 years ago
How it is come? Please explain the answer.
Jagdish said:
7 years ago
How? anyone explain me please.
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