Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 4 (Q.No. 34)
34.
If 50 kg of fine aggregates and 100 kg of coarse agregates are mixed in a concrete whose water cement ratio is 0.6, the weight of water required for harsh mix, is
Discussion:
41 comments Page 5 of 5.
Aryan said:
2 years ago
@All.
W/c * cement = 0.3 * cement + 0.1 * fine aggregate + 0.01 * coarse aggregate.
0.6 * C = 0.3 * C + 0.1 * 50 + 0.01 * 100.
C = 20KG.
W/C * Cement = wt of water.
= 0.6 * 20 = 12 kg.
W/c * cement = 0.3 * cement + 0.1 * fine aggregate + 0.01 * coarse aggregate.
0.6 * C = 0.3 * C + 0.1 * 50 + 0.01 * 100.
C = 20KG.
W/C * Cement = wt of water.
= 0.6 * 20 = 12 kg.
(11)
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