Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 4 (Q.No. 34)
34.
If 50 kg of fine aggregates and 100 kg of coarse agregates are mixed in a concrete whose water cement ratio is 0.6, the weight of water required for harsh mix, is
Discussion:
41 comments Page 2 of 5.
SANJEEV KR ANAD said:
9 years ago
W/c *p = 0.3p +0.1F +0.01C.
0.6*p = 0.3p + 0.1*50 +0.01*100,
0.3p = 5+1,
P = 6 ÷ 0.3,
P = 20.
Then, water= w/c*P =0.6 * 20 = 12kg ans.
0.6*p = 0.3p + 0.1*50 +0.01*100,
0.3p = 5+1,
P = 6 ÷ 0.3,
P = 20.
Then, water= w/c*P =0.6 * 20 = 12kg ans.
Madhu ratan said:
5 years ago
Weight of water = (5%wt.of coarse aggregate +30%wt. Of fine aggregate)*W/C ratio.
= ( 5 * 100/100 + 30 * 50/100) * 0.6.
= 12kg.
= ( 5 * 100/100 + 30 * 50/100) * 0.6.
= 12kg.
Sameer Khan said:
4 years ago
Where does this formula comes from?
W/C *P = 0.3P + 0.1F.A +.01C.A
How do you justify it? Please explain me.
W/C *P = 0.3P + 0.1F.A +.01C.A
How do you justify it? Please explain me.
(3)
Mir Imroz said:
4 years ago
In harsh mix weight of water =. 30% wt of fine aggregate + .05% wt of coarse aggregate) water-cement ratio.
(3)
Er vikash saini said:
4 years ago
Here 50 kg weight of cement:
M 25 ratio 1:1:2.
(5% weight of aggregate + 30 weight of cement)w/c ratio.
M 25 ratio 1:1:2.
(5% weight of aggregate + 30 weight of cement)w/c ratio.
(4)
Bivek Pradhanang said:
9 years ago
D. w= 5%aggregate + 30%cement and here w/c=0.6.
So, here w= .05 * [50+150]+.3 * [w/0.6], so w = 15kg.
So, here w= .05 * [50+150]+.3 * [w/0.6], so w = 15kg.
Hussain said:
8 years ago
W= 30%cement +4%of total aggregates.
W=. 3W/.6+.04*150 (Given- Water/Cement =0.6).
W=. 5W+6.
W=12kg.
W=. 3W/.6+.04*150 (Given- Water/Cement =0.6).
W=. 5W+6.
W=12kg.
Ak jain said:
8 years ago
Please solve,
How to find the water required for concrete 1:2:4 if w/c =.6 and unit w.=2400kg/m3?
How to find the water required for concrete 1:2:4 if w/c =.6 and unit w.=2400kg/m3?
Amit mishra said:
6 years ago
Water content = 5/100 * (weight of aggregate) + 30/100 * (wt of cement).
So the answer is 15 kg.
So the answer is 15 kg.
Sumit said:
1 decade ago
100 (wt.of Coarse sand) *5/100 = 5 kg.
50 (wt.of cement)* 30/100 = 15 kg.
(5+15)*0.6 = 12 kg.
50 (wt.of cement)* 30/100 = 15 kg.
(5+15)*0.6 = 12 kg.
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