Civil Engineering - Concrete Technology - Discussion

W/C *P = 0.3P + 0.1F.A +.01C.A.
0.6*P =0.3P + 0.1(50) + 0.01(100),
0.6P - 0.3P = 5 + 1,
P = 6/0.3,
P = 20 => Where P= Cement.

Now;
W/C = 0.6,
W = C * 0.6,
W = 20 * 0.6,
W = 12Kg.

Weight of water = (5%wt.of coarse aggregate +30%wt. Of fine aggregate)*W/C ratio.
= ( 5 * 100/100 + 30 * 50/100) * 0.6.
= 12kg.

DEAR all, First of all, pick the question, In the question, we are asked for two quantities not for one. We have to fine cement as well as water.

Therefore We know that,

Weight of water / Weight of cement = Water to cement ratio.
And the water to cement ratio is 0.6.

Rearrange the above formula,

Weight of water = Weight of cement x Water to cement ratio.

So,
Weight of water = Weight of cement x 0.6.....................(i)
Here, We have in weight of water =
0.3 x weight of cement + 0.1 x fine aggregate + 0.1 x coarse aggregate=
0.3 x weight of cement + 0.1 x (50)+ 0.1 x (100) = 0.3 x weight of cement + 5 +1
0.3 x weight of cement + 0.1 x (50)+ 0.1 x (100) = 0.3 x weight of cement +6.

So,
Weight of water = 0.3 x weight of cement +6...........................(ii)

From equation 1,
Weight of cement x 0.6 = 0.3 x weight of cement + 6.
Let weight of cement be denoted by L
L x 0.6 =0.3 x L + 6
0.6 L-0.3 L = 6
0.3 L = 6
L = 6/ 0.3= 20 kg.
Where L is the weight of cement.

By using formula,
Weight of water = weight of cement x water to cement ratio.
Weight of water = 20 x 0.6.
= 12 kg.

0.3 * cement + 0.1fine + 0.01coarse = 0.6 * cement.
0.3 * cent + 0.1 * 50 + .0.01 * 100 = 0.6 * cement.
0.3 * cement = 6.

Cement = 20,
W/c = 0.6,
W = 0.6 * 20 = 12kg.

Water content = 5/100 * (weight of aggregate) + 30/100 * (wt of cement).
So the answer is 15 kg.

Thanks all for explaining it.

W/C * P = 0.3P + 0.1F.A +.01C.A.
0.6 * P = 0.3P + 0.1(50) + 0.01(100),
0.6P - 0.3P = 5 + 1,
P = 6/0.3
P = 20 => Where P= Cement.

Now;
W/C = 0.6,
W = C * 0.6,
W = 20 * 0.6,
W = 12Kg.

How to find out 5% CA and 30% FA?

W/C *P = 0.3P + 0.1F.A +.01C.A
0.6*P=0.3P+0.1(50)+0.01(100)
0.6P-0.3P=5+1
P=6/0.3
P=20 => Where P= Cement.
Now;
W/C=0.6,
W=C*0.6,
W=20*0.6,
W=12Kg.

Thank you so much for explaining it.