Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 1 (Q.No. 29)
29.
If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is
Discussion:
44 comments Page 3 of 5.
Virendra kumar said:
8 years ago
How to total 740 and what is 740? please explain.
HARSHA G said:
9 years ago
SIEVE WEIGHT RET CUMULATIVE WT CUM.%
SIZE
80 0 0 0
40 2 2 10
20 8 10 50
10 6 16 80
4.75 4 20 100
2.36 0 20 100
1.18 0 20 100
600M 0 20 100
300M 0 20 100
150M 0 20 100
ADD CUM % RET AND DIVIDE BY 100 740/100 = 7.4.
Fineness modulus is an empirical factor obtained by adding the cumulative percentages of aggregate retained on each of the standard sieves ranging from 80 mm to 150 micron and dividing this sum by 100.
CUM% = (CUM WT / TOTAL WT )* 100.
SIZE
80 0 0 0
40 2 2 10
20 8 10 50
10 6 16 80
4.75 4 20 100
2.36 0 20 100
1.18 0 20 100
600M 0 20 100
300M 0 20 100
150M 0 20 100
ADD CUM % RET AND DIVIDE BY 100 740/100 = 7.4.
Fineness modulus is an empirical factor obtained by adding the cumulative percentages of aggregate retained on each of the standard sieves ranging from 80 mm to 150 micron and dividing this sum by 100.
CUM% = (CUM WT / TOTAL WT )* 100.
Dangerous said:
9 years ago
Sieve Retained Reained perce Cumaltive size
80 0 0 0
40 2 10 10
20 8 40 50
10 6 30 80
4.75 4 20 100
2.36 0 0 100
1.18 0 0 100
600 0 0 100
300 0 0 100
150 0 0 100
740
Fineness modulus =740/100,
= 7.4.
80 0 0 0
40 2 10 10
20 8 40 50
10 6 30 80
4.75 4 20 100
2.36 0 0 100
1.18 0 0 100
600 0 0 100
300 0 0 100
150 0 0 100
740
Fineness modulus =740/100,
= 7.4.
Moreri said:
9 years ago
Why do we divide 740 by 100?
Umang said:
9 years ago
Thanks for the explanation @Maha.
Abi said:
9 years ago
Can't understand. Please explain this.
Sudip said:
9 years ago
Sieve.size wt. retained(kg) %wt.retained(%) cumulative%
80 0 0 0.
40 2 10 10.
20 8 40 50.
10 6 30 80.
7.5 4 20 100.
4.75 0 0 100.
2.36 0 0 100.
1.18 0 0 100.
600 0 0 100.
300 0 0 100.
150 0 0 100.
-----------------
Total = 740.
-----------------
Fineness modulus of given course aggregate is 740/100 = 7.4.
For wt. retained in %, for 40mm sieve size, (2/20)*100% where 20 is the total wt.
80 0 0 0.
40 2 10 10.
20 8 40 50.
10 6 30 80.
7.5 4 20 100.
4.75 0 0 100.
2.36 0 0 100.
1.18 0 0 100.
600 0 0 100.
300 0 0 100.
150 0 0 100.
-----------------
Total = 740.
-----------------
Fineness modulus of given course aggregate is 740/100 = 7.4.
For wt. retained in %, for 40mm sieve size, (2/20)*100% where 20 is the total wt.
Sanjana said:
9 years ago
Can anyone explain last column?
Naman said:
9 years ago
I didn't get this, Please explain briefly.
Bapureddy said:
9 years ago
I didn't get it. Please, Can anyone explain it clearly?
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