Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 2 (Q.No. 30)
30.
A 50 kg boy climbs up a 8 m rope in gymnasiam in 10 sec. The average power developed by the boy is approximately
Discussion:
4 comments Page 1 of 1.
Naeem said:
9 years ago
Nice, well explained @Suhasini & @Asay.
Ehsan said:
9 years ago
Well explained.
Asay said:
9 years ago
Power = Work done/Time.
Work done = Force * Distance.
= 50 * 10 * 8 = 4000 N - m
Power = 4000/10 = 400 N-m/s = 400 watts.
Work done = Force * Distance.
= 50 * 10 * 8 = 4000 N - m
Power = 4000/10 = 400 N-m/s = 400 watts.
(2)
Suhasini said:
1 decade ago
Power = Work done/Time.
Work done = Force*Distance.
= 50*8 = 400 kgm.
Power = 400/10 = 40 kgm/s = 392.3 watts approximately 400 watts.
Work done = Force*Distance.
= 50*8 = 400 kgm.
Power = 400/10 = 40 kgm/s = 392.3 watts approximately 400 watts.
(4)
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