Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 3 (Q.No. 19)
19.
Two shots fired simultaneously from the top and bottom of a vertical tower with elevations of 30° and 45° respectively strike a target simultaneously. If horizontal distance of the target from the tower is 1000 m, the height of the tower is
Discussion:
3 comments Page 1 of 1.
Sufazo said:
9 years ago
1/3 * 3/2 * 1000 = 500.
Now we have two angle 30 + 45 = 75, 500 - 75, 425.
Now we have two angle 30 + 45 = 75, 500 - 75, 425.
Rajesh said:
7 years ago
H = a( tan45 - tan30).
a = 1000m.
a = 1000m.
Amal zad said:
6 years ago
Please, anyone explains in detail.
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