Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 2 (Q.No. 46)
46.
Ball A of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/s hits an identical stationary ball B on the table. If the impact is perfectly elastic, the velocity of the ball B just after impact would be
Discussion:
1 comments Page 1 of 1.
Kush Kakkar said:
9 years ago
Law of conservation:
Initial of ball = final of ball.
m1u1 + m2u2 = m1v1 + m2v2.
250x10 + 250x0 = 250x0 + 250x v2,
v2 = 10 m/sc.
Initial of ball = final of ball.
m1u1 + m2u2 = m1v1 + m2v2.
250x10 + 250x0 = 250x0 + 250x v2,
v2 = 10 m/sc.
(1)
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