Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 3 (Q.No. 7)
7.
The motion of a particle is described by the relation x = t2- 10t + 30, where x is in metres and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be
Discussion:
4 comments Page 1 of 1.
Mukul mahi said:
6 years ago
V= t^2 - 10t + 30.
dv/dx = 2t - 10.
If t=0,
So 2 x 0 - 10 = -10.
If t = 10,
So 2 x 10 - 10 = 20 - 10 = 10.
Total distance 10-10 = 0 Answer.
dv/dx = 2t - 10.
If t=0,
So 2 x 0 - 10 = -10.
If t = 10,
So 2 x 10 - 10 = 20 - 10 = 10.
Total distance 10-10 = 0 Answer.
(2)
Eeranna said:
9 years ago
Substitute time t = 0, in the equation of x, x = 30 m.
Time t = 10, in the equation of x, x = 30 m.
Both are same, means the body is in the rest condition.
So, the distance is zero.
Time t = 10, in the equation of x, x = 30 m.
Both are same, means the body is in the rest condition.
So, the distance is zero.
(1)
Sadulla said:
7 years ago
It's not in rest. But it returns back to the starting point.
Arj said:
7 years ago
The total distance is 50 and displacement is zero.
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