Civil Engineering - Applied Mechanics - Discussion

Consider it to a triangle instead of a parabola, then the distance of C.G. from Y-axis would be 2*a/3=0.66*a.

But now, it's a parabola, so the centroid has shifted away from Y-axis, so the answer should be > 0.66*a.

Now, option A gives 0.25*a which is less than 0.66*a, so option A eliminated.
option C is eliminated since the distance is asked from Y-axis and not X-axis.
Option D = 0.3*a<0.66*a, so eliminated,
Option E = 0.6*a<0.66*a, so eliminated.
Hence, correct answer is option B = 0.75*a.

We all know the equation of a parabola given by Y^2= 4aX the centre of gravity for y coordinate is given by y = integral of y^2/2 from 0 to a divided by the integral of y from 0 to a.

After doing the calculations the answer will be 3a/4.

Just because it's direction is opposite it's value is sub by 1.

When solved with a known value of 'A' I got the right answer.

The given Answer is right if it is a quadric parabola.

From x-axis = 3a/4.
And from Y-axis = 3b/10.

From y-axis 3a/4.

From x-axis 3b/10.

Area = 1/3 * ab,
X = 3a/4,
Y = 1/4a.

It's from y-axis so 1-(3a/4) =3a/4.

Can anybody explain it? Please.