Civil Engineering - Applied Mechanics - Discussion

Discussion Forum : Applied Mechanics - Section 3 (Q.No. 5)
5.
The resultant of two forces acting at right angles is 5 kgf and if they act at an angle of 60°, it is 37 kgf. The magnitudes of the forces are :
2 kgf, 3 kgf
3 kgf, 4 kgf
4 kgf, 5 kgf
5 kgf, 3 kgf.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.

ER AKBAR said:   3 years ago
@All.

It's so simple! put the answer (a,b,c,d,e) in formula i.e by taking square on both sides 34=3^2 +5^2.

34 => 9+25.

Kishor said:   8 years ago
First acting 90" angle then = 5^2=p^2 +Q^2.

If acting 60" then=37=p^2+q^2+2pq cos 60"=25+pq.
Then pq=12.
solve it.

Kanhaiya said:   8 years ago
How to solve this? Please tell me.

Aparna dubey said:   8 years ago
How to solve it? Describe.

Eeranna said:   9 years ago
By verification of answers.

Take p=3 kgf, q=4kgf, angle is 60°.

Find out the resultant value,

We are getting the value root 37.

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