Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 3 (Q.No. 5)
5.
The resultant of two forces acting at right angles is 5 kgf and if they act at an angle of 60°, it is 37 kgf. The magnitudes of the forces are :
Discussion:
5 comments Page 1 of 1.
ER AKBAR said:
3 years ago
@All.
It's so simple! put the answer (a,b,c,d,e) in formula i.e by taking square on both sides 34=3^2 +5^2.
34 => 9+25.
It's so simple! put the answer (a,b,c,d,e) in formula i.e by taking square on both sides 34=3^2 +5^2.
34 => 9+25.
Kishor said:
8 years ago
First acting 90" angle then = 5^2=p^2 +Q^2.
If acting 60" then=37=p^2+q^2+2pq cos 60"=25+pq.
Then pq=12.
solve it.
If acting 60" then=37=p^2+q^2+2pq cos 60"=25+pq.
Then pq=12.
solve it.
Kanhaiya said:
8 years ago
How to solve this? Please tell me.
Aparna dubey said:
8 years ago
How to solve it? Describe.
Eeranna said:
9 years ago
By verification of answers.
Take p=3 kgf, q=4kgf, angle is 60°.
Find out the resultant value,
We are getting the value root 37.
Take p=3 kgf, q=4kgf, angle is 60°.
Find out the resultant value,
We are getting the value root 37.
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