Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 3)
3.
At a given instant ship A is travelling at 6 km/h due east and ship B is travelling at 8 km/h due north. The velocity of B relative to A is
Discussion:
22 comments Page 1 of 3.
Gaurav gupta said:
1 decade ago
By using pythagoras theorem;
(8*8) + (6*6) equal to 100 and square root of 100 is 10.
(8*8) + (6*6) equal to 100 and square root of 100 is 10.
Saurabh said:
1 decade ago
It should be 10. Why it is 14 anyone explain this?
Ankur padalia said:
1 decade ago
Using the pythagoras theorem.
Amol Ashok Lande said:
1 decade ago
(V)x = 6.
(V)y = 8.
Vb/a = (36+64)^1/2.
Vb/a = 10 km/hr.
(V)y = 8.
Vb/a = (36+64)^1/2.
Vb/a = 10 km/hr.
Saleem khan said:
1 decade ago
Both force are acting on right angle so we will find resultant acc to parallelogram law. R^2 = f1^2 + f2^2 + cos90.
But there is value of cos90 = 0.
But there is value of cos90 = 0.
ABDUL SALAM ANSARI said:
1 decade ago
Both force are acting on right angle so, we will find resultant according to parallelogram law.
R^2 = f1^2 + f2^2 +2f1*f2*cos90.
But there is value of cos90 = 0.
We know,
f1 = 6km/hr and f2 = 8km/hr.
R^2 = 6^2+8^2+2*6*8*0.
=> R^2 = 36+64.
=> R = (100)^1/2.
=> R = 10km/hr.
R^2 = f1^2 + f2^2 +2f1*f2*cos90.
But there is value of cos90 = 0.
We know,
f1 = 6km/hr and f2 = 8km/hr.
R^2 = 6^2+8^2+2*6*8*0.
=> R^2 = 36+64.
=> R = (100)^1/2.
=> R = 10km/hr.
CHANDAN KUMAR said:
1 decade ago
The force are acting at right angle so simply you know that find resultant r^2 = p^2+Q^2.
Assume p = 6, q = 8 substitute this values.
r^2 = 6^2+8^2.
r^2 = 36+64.
r^2 = 100.
Now do the square root of 100 is 10.
Thus r = 10km/hr.
Assume p = 6, q = 8 substitute this values.
r^2 = 6^2+8^2.
r^2 = 36+64.
r^2 = 100.
Now do the square root of 100 is 10.
Thus r = 10km/hr.
A KUMAR said:
1 decade ago
Va = 6i+0j, Vb = 0i+8j.
Vba = Vb-Va.
6i+0j-(0i+8j) = 6i-8j.
Magnitude of Vba = (6^2+8^2)^1/2.
= (100)^1/2.
= 10 mtr/sec.
Vba = Vb-Va.
6i+0j-(0i+8j) = 6i-8j.
Magnitude of Vba = (6^2+8^2)^1/2.
= (100)^1/2.
= 10 mtr/sec.
Usama ahmad said:
1 decade ago
6*6+8*8=100 s of 100=10.
Nitesh jayswal said:
9 years ago
By using Pythagoras theorem:-
8 * 8 + 6 * 6 = 100.
Square root of 100 = 10km/hr.
8 * 8 + 6 * 6 = 100.
Square root of 100 = 10km/hr.
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