Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 2 (Q.No. 4)
4.
Two forces of 6 Newtons and 8 Newtons which are acting at right angles to each other, will have a resultant of
Discussion:
3 comments Page 1 of 1.
SHILPA said:
1 decade ago
Resultant R = sqrt(A2+B2).
A = 6.
B = 8 substitute A, B.
R = sqrt(100).
R = 10 N.
A = 6.
B = 8 substitute A, B.
R = sqrt(100).
R = 10 N.
Hari Prasanna said:
9 years ago
P = 6.
Q = 8.
R = (P^2 + Q^2 + 2PQ cosa)^1/2.
(where 'a' is the angle between the forces 'P' and 'Q').
So,
R = (36 + 64 = 2 * 6 * 8 * cos90)^1/2.
Then, R = 10.
Q = 8.
R = (P^2 + Q^2 + 2PQ cosa)^1/2.
(where 'a' is the angle between the forces 'P' and 'Q').
So,
R = (36 + 64 = 2 * 6 * 8 * cos90)^1/2.
Then, R = 10.
(1)
Eeranna said:
9 years ago
The above explanations are correct. Thanks.
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