Civil Engineering - Applied Mechanics - Discussion

Discussion Forum : Applied Mechanics - Section 3 (Q.No. 40)
40.
If the linear velocity of a point on the rim of a wheel of 10 m diameter, is 50 m/sec, its angular velocity will be
20 rad/sec
15 rad/sec
10 rad/sec
5 rad/sec.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Manesh kumar said:   2 years ago
The right answer should be option C.

Rashid said:   6 years ago
v = rw.

=> w = v/r ~ d=10=> r = 5.

=> w = 50/5.

w = 10rad/sec.

Asheesh saini said:   8 years ago
Linear velocity = angular velocity * radius.
v= wr
where d=10 , v= 50m/s, r=d/2 = 10/2 =5.

So w=v/r w= 50/5 = 10 radian/sec.

Soraj said:   9 years ago
w = v/r.
where,
d = 10,so,
r = 5
w = 50/5 = 10.

Mark said:   9 years ago
How is it? Describe me.

Vyankatesh said:   9 years ago
Formulae for linear velocity ; Ωr, my answer is from this formulae is 10 rad/s.

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