Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 8)
8.
The unit of Moment of Inertia of a body, is
Discussion:
3 comments Page 1 of 1.
Vahinisri said:
9 years ago
Example: for a rectangle, a moment of inertia I = (bh^3) /12.
Breadth b's dimension will be in m or mm or cm.
Height h's dimension also will be in m or mm or cm (in cube).
Hence, the answer is (units' product) m * m^3 = m^4.
Breadth b's dimension will be in m or mm or cm.
Height h's dimension also will be in m or mm or cm (in cube).
Hence, the answer is (units' product) m * m^3 = m^4.
Harsh C. Patel said:
8 years ago
For Rectangle M.I. = b*d^3 / 12.
Where b= width of rectangle & d= depth of rectangle,
so, S.I. unit of width and depth are mm or m or cm etc.
Hence, m*m^3 = m^4.
So, our answer is m^4.
Where b= width of rectangle & d= depth of rectangle,
so, S.I. unit of width and depth are mm or m or cm etc.
Hence, m*m^3 = m^4.
So, our answer is m^4.
Sravya said:
10 years ago
I agree with this answer and be alert with dimensions like mm, cm, inch etc.
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