Discussion :: Applied Mechanics - Section 1 (Q.No.21)
|M Zafar said: (Apr 5, 2015)|
|Any one explain how?|
|Jay Bermudo said: (May 12, 2015)|
|If you look closely, there are three cables in the problem. It says the word "lift" three times so the cable is three. So gravity divided by three is the answer.|
|Amr said: (Jul 19, 2015)|
|According to motion equation sum of forces = mass*acceleration (a).
In case going down force up is tension t and down is weight mass*g.
So m*g-t = m*a.
So t = m*g-m*a....(1).
In case of going up force up is 2*t and force down is m*g.
So 2*t-m*g = m*a.
So from 1 t = m*g-m*a then 2*m*g-2*m*a-m*g = m*a.
Then m*g-2*m*a = m*a.
So m*g = 3*m*a. So g = 3 a.
So a = g/3.
|Kiran said: (May 21, 2017)|
|Yes, your explanation is correct @Amr.|
|Suneel Kurmi said: (May 30, 2017)|
|Tension in the cable.
Moving downward T= m(g-a).
B option is correct.
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