Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 3 (Q.No. 15)
15.
If G is the Gauge of track, v is velocity of the moving vehicle, g is the acceleration due to gravity and r is the radius of a circular path, the required superelevation is
Discussion:
11 comments Page 1 of 2.
Dhaval said:
8 years ago
According to me, It should be Gv^2/gr.
Chhaya said:
8 years ago
Yes, Right @Dhaval.
Tushar said:
8 years ago
Yes, according to me, it also Gv2/gr.
Khan said:
8 years ago
How it will be solved? Please explain.
Tep said:
7 years ago
It's Gv^2/gr.
Prashant Nagpure said:
7 years ago
Yes, according to me, it also Gv2/gr.
Grishma said:
6 years ago
Gv2/gr is correct one.
Namita said:
6 years ago
Gv^2/gr is correct.
Yasir Jadoon said:
5 years ago
Yes it is Gv^2/gr.
Umati said:
3 years ago
S = G.v^2/g.r.
G = gauge of the track.
G = gauge of the track.
(1)
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