Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 40)
40.
The length of a Second's pendulum, is
Discussion:
3 comments Page 1 of 1.
Delwyn Alcaraz said:
4 years ago
L= g/π^2.
L = 9.81/(3.14^2),
L = 99.4m.
L = 9.81/(3.14^2),
L = 99.4m.
(2)
Kush Kakkar said:
9 years ago
T = 2ω * L/G.
Put T= 2 Sec, G= 9.81 you get L = 0.994.
A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing.
Put T= 2 Sec, G= 9.81 you get L = 0.994.
A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing.
(1)
SUNIL said:
9 years ago
CALCULATION:
1 = (3.14^2) * L/9.81.
Then,
L = 0.994m.
1 = (3.14^2) * L/9.81.
Then,
L = 0.994m.
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