Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 12)
12.
A particle moves along a straight line such that distance x traversed in t seconds is given by x = t2(t + 1), the acceleration of the particle, will be
Discussion:
13 comments Page 2 of 2.
Shobhit pal said:
5 years ago
X = t^3 + t^2.
dx/dt = 3t^2 + 2t.
dx^2/dt^2 = 6t + 2.
dx/dt = 3t^2 + 2t.
dx^2/dt^2 = 6t + 2.
(1)
Mohbat Khan Marri said:
8 years ago
t^2(t+1).
=t^3+t^2,
dx/dt=3t^2+2t,
dx^2/dt^2=6t+2.
=t^3+t^2,
dx/dt=3t^2+2t,
dx^2/dt^2=6t+2.
BVC said:
8 years ago
x=t3+t2,
dx/dt=3t2+2T,
d2x/d2t=6T+2,
Ans: D.
dx/dt=3t2+2T,
d2x/d2t=6T+2,
Ans: D.
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