Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 12)
12.
A particle moves along a straight line such that distance x traversed in t seconds is given by x = t2(t + 1), the acceleration of the particle, will be
Discussion:
13 comments Page 2 of 2.
Nilesh gagare said:
8 years ago
T2(t+1)
T3+t.
Diff w.r.t:t
3t2+1.
Again diff w.r.t:t
6t.
And the answer is 6t.
T3+t.
Diff w.r.t:t
3t2+1.
Again diff w.r.t:t
6t.
And the answer is 6t.
BVC said:
8 years ago
x=t3+t2,
dx/dt=3t2+2T,
d2x/d2t=6T+2,
Ans: D.
dx/dt=3t2+2T,
d2x/d2t=6T+2,
Ans: D.
Mohbat Khan Marri said:
8 years ago
t^2(t+1).
=t^3+t^2,
dx/dt=3t^2+2t,
dx^2/dt^2=6t+2.
=t^3+t^2,
dx/dt=3t^2+2t,
dx^2/dt^2=6t+2.
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