Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 2 (Q.No. 20)
20.
A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is
Discussion:
8 comments Page 1 of 1.
Kush Kakkar said:
9 years ago
If the particle moves with the velocity of 2 meters in a second. Then to cover the distance of 1.5 meters obvious it takes less than one second.
So, I think the question is wrong.
So, I think the question is wrong.
Atal bajpai said:
9 years ago
V = u+at,
2 = 0+0.1*t,
t = 2\0.1=20 sec.
2 = 0+0.1*t,
t = 2\0.1=20 sec.
Sufazo said:
9 years ago
2-0.4 = 1.6 * 1.5 = 2.0 * 10 = 20.
Pavan said:
8 years ago
Here, S = ut+1/2 a t square.
Sadulla said:
7 years ago
Right @Kush Kakkar.
The Answer will be 0.76 seconds.
The Answer will be 0.76 seconds.
Ali Asghar said:
6 years ago
The answer should be 0.76 seconds.
After exactly 20 seconds body comes to rest.
After exactly 20 seconds body comes to rest.
Vishal Gahane said:
6 years ago
0.76 seconds is the wrong answer. Negative acceleration should be considered.
Muhammad said:
5 years ago
S=ut+1/2at^2 is the right equation to solve this.
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