Civil Engineering - Applied Mechanics - Discussion

3. 

A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is

[A]. 17° 48'
[B]. 18° 48'
[C]. 19° 48'
[D]. 20° 48'
[E]. 21° 48'.

Answer: Option C

Explanation:

No answer description available for this question.

Izat Nawaz said: (Apr 30, 2016)  
Please give the complete solution of the above question. How you solve this?

Priyanka said: (Jan 11, 2017)  
Angle of friction,
tanA = maximum force of friction/normal reaction.
tanA = 18/50 = 0.36.
A = tan (0.36) = 19' 48'.

Rakesh Kumar said: (Jul 6, 2018)  
Thanks @Priyanka.

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