Civil Engineering - Applied Mechanics - Discussion

Discussion Forum : Applied Mechanics - Section 4 (Q.No. 3)
3.
A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is
17° 48'
18° 48'
19° 48'
20° 48'
21° 48'.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Rakesh kumar said:   7 years ago
Thanks @Priyanka.

PRIYANKA said:   8 years ago
Angle of friction,
tanA = maximum force of friction/normal reaction.
tanA = 18/50 = 0.36.
A = tan (0.36) = 19' 48'.
(1)

Izat Nawaz said:   9 years ago
Please give the complete solution of the above question. How you solve this?

Post your comments here:

Your comments will be displayed after verification.