Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 4 (Q.No. 3)
3.
A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is
Discussion:
3 comments Page 1 of 1.
Rakesh kumar said:
7 years ago
Thanks @Priyanka.
PRIYANKA said:
8 years ago
Angle of friction,
tanA = maximum force of friction/normal reaction.
tanA = 18/50 = 0.36.
A = tan (0.36) = 19' 48'.
tanA = maximum force of friction/normal reaction.
tanA = 18/50 = 0.36.
A = tan (0.36) = 19' 48'.
(1)
Izat Nawaz said:
9 years ago
Please give the complete solution of the above question. How you solve this?
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