Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 3 (Q.No. 29)
29.
The moment of inertia of a hollow circular section whose external diameter is 8 cm and internal diameter is 6 cm, about centroidal axis, is
Discussion:
5 comments Page 1 of 1.
Ramesh said:
9 years ago
(3.14 / 64).(8^4 - 6^4) = 137.375.
(1)
Tep said:
7 years ago
The formula is π/64 (D^4-d^4).
Rohit Kumar said:
8 years ago
3.14*(8^4-6^4)÷64=137.5.
(1)
Dave said:
7 years ago
Please explain the formula.
Sachin Singh said:
7 years ago
Explain the formula.
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