# Civil Engineering - Applied Mechanics - Discussion

Discussion Forum : Applied Mechanics - Section 4 (Q.No. 4)

4.

From a circular plate of a diameter 6 cm is cut out a circle whose diameter is equal to the radius of the plate. The C.G. of the remainder from the centre of circular plate is at a distance of

Discussion:

7 comments Page 1 of 1.
Aman said:
3 years ago

Thanks all for explaining.

(1)

Swapnalatha said:
4 years ago

R/D = 3/6 = 0.5.

(1)

Lalan kumar said:
5 years ago

R/D = cg.

3/6 = .5.

3/6 = .5.

Avinash said:
5 years ago

X = 5R/6.

= 5(3)/6,

=2.5.

X is the distance of the centroid from the end in the question he asked distance of the centroid from centre.

Circle centre at 3 so;

3-2.5= 0.5 is the answer.

= 5(3)/6,

=2.5.

X is the distance of the centroid from the end in the question he asked distance of the centroid from centre.

Circle centre at 3 so;

3-2.5= 0.5 is the answer.

(1)

Bhoopender chauhan said:
6 years ago

C.g of reminder from centre is R/6.

And from end is 7R/6,

So a/q.

From centre of plate R/6=3/6=.5

And from end is 7R/6,

So a/q.

From centre of plate R/6=3/6=.5

Pavan b said:
6 years ago

r/R = 1.5/3.0 = 0.5.

So,

C.G of the circle acts on the center of a circle.

So,

C.G of the circle acts on the center of a circle.

Rajesh thakur said:
7 years ago

On x - axis, X= R * 3 -r * 3/R * 2 - r * 2 = 3 * 3 - 1.5 * 3/3 * 3 - 1.5 * 2 = 3.5cm,

Hence distance of centre of gravity of remainder from centre of circle.

3.5 - 3 = 0.5.

Hence distance of centre of gravity of remainder from centre of circle.

3.5 - 3 = 0.5.

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