Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 4 (Q.No. 4)
4.
From a circular plate of a diameter 6 cm is cut out a circle whose diameter is equal to the radius of the plate. The C.G. of the remainder from the centre of circular plate is at a distance of
Discussion:
7 comments Page 1 of 1.
Aman said:
4 years ago
Thanks all for explaining.
(1)
Swapnalatha said:
5 years ago
R/D = 3/6 = 0.5.
(1)
Lalan kumar said:
5 years ago
R/D = cg.
3/6 = .5.
3/6 = .5.
Avinash said:
6 years ago
X = 5R/6.
= 5(3)/6,
=2.5.
X is the distance of the centroid from the end in the question he asked distance of the centroid from centre.
Circle centre at 3 so;
3-2.5= 0.5 is the answer.
= 5(3)/6,
=2.5.
X is the distance of the centroid from the end in the question he asked distance of the centroid from centre.
Circle centre at 3 so;
3-2.5= 0.5 is the answer.
(2)
Bhoopender chauhan said:
7 years ago
C.g of reminder from centre is R/6.
And from end is 7R/6,
So a/q.
From centre of plate R/6=3/6=.5
And from end is 7R/6,
So a/q.
From centre of plate R/6=3/6=.5
Pavan b said:
7 years ago
r/R = 1.5/3.0 = 0.5.
So,
C.G of the circle acts on the center of a circle.
So,
C.G of the circle acts on the center of a circle.
Rajesh thakur said:
8 years ago
On x - axis, X= R * 3 -r * 3/R * 2 - r * 2 = 3 * 3 - 1.5 * 3/3 * 3 - 1.5 * 2 = 3.5cm,
Hence distance of centre of gravity of remainder from centre of circle.
3.5 - 3 = 0.5.
Hence distance of centre of gravity of remainder from centre of circle.
3.5 - 3 = 0.5.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers