Civil Engineering - Advanced Surveying - Discussion
Discussion Forum : Advanced Surveying - Section 2 (Q.No. 10)
10.
The net ground area of a vertical photograph 20 cm x 20 cm on scale 1 : 10,000 having overlaps 60% and 30%, is
Discussion:
10 comments Page 1 of 1.
Abdus Samad Khan said:
4 years ago
1cm = .1sqkm.
So 2*2 = 4cm = .4sqkm,
Now 90% of .4=.36,
Thanks @Bishnu Khatri.
So 2*2 = 4cm = .4sqkm,
Now 90% of .4=.36,
Thanks @Bishnu Khatri.
Prakash said:
5 years ago
0.9 * 4=0.36
Rahul Thakur said:
5 years ago
Yes, the correct answer is 1.12 sqkm.
(2)
Ananga said:
5 years ago
l = 20 cm.
w = 20cm.
S= (1/10000),
Pl = 0.6.
Pw = 0.3.
Ground area = (1-0.6)*(1-0.3)*(0.2 *0.2)*(10^2) sqkm.
= 1.12 sqkm.
w = 20cm.
S= (1/10000),
Pl = 0.6.
Pw = 0.3.
Ground area = (1-0.6)*(1-0.3)*(0.2 *0.2)*(10^2) sqkm.
= 1.12 sqkm.
(1)
Abhishek Taware said:
5 years ago
The correct answer is 1.12 sqkm.
(1)
Jamil Ahmed Mazumder said:
6 years ago
Area = L*W.
= l/s*. 40*w/s *. 70.
= 1.2square km.
= l/s*. 40*w/s *. 70.
= 1.2square km.
(1)
Subhajit Dutta said:
7 years ago
Yes, the Correct answer will be 1.12 sqkm.
Sajid said:
7 years ago
According to me, The correct answer is 1.12 sq Km.
(1)
Ankit said:
7 years ago
90% of 4 sq.km = 3.6 sq.km, then how does it come to 0.36 sq.km?
Please clarify.
Please clarify.
Bishnu Khatri said:
10 years ago
RF scale 1:10000 = Engineering Scale = (1 cm = 0.1 km).
Area of vertical photograph = 20 cm x 20 cm = (2 km x 2 km) = 4 sq.Km.
Total overlap = 60+30 = 90%.
Total overlap area = 90% of 4 sq.Km = 0.36 sq.Km.
Net area = 1 sq.Km - 0.36 sq.Km = 0.64 sq.Km.
Area of vertical photograph = 20 cm x 20 cm = (2 km x 2 km) = 4 sq.Km.
Total overlap = 60+30 = 90%.
Total overlap area = 90% of 4 sq.Km = 0.36 sq.Km.
Net area = 1 sq.Km - 0.36 sq.Km = 0.64 sq.Km.
(4)
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