Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 7)
7.
A very dilute solution is prepared by dissolving 'x1' mole of solute in 'x2' mole of a solvent. The mole fraction of solute is approximately equal to
Discussion:
5 comments Page 1 of 1.
Sanjoy karmakar said:
5 years ago
Thank you @Ria Chaudhury.
Dharmik said:
5 years ago
Thanks @Riachaudhury.
Pratap said:
5 years ago
Right, Thanks @Ria Chaudhury.
Trushal said:
7 years ago
Thank you for explaining @Ria Chaudhury.
RIA CHAUDHURY said:
1 decade ago
Mole fraction of solute = (moles of sole)/(total no of moles) = x1/ (x1+x2).
But x2>>>x1 (since the solution is dilute).
So x1 can be neglected in the denominator.
Hence mole fraction of solute = x1/x2.
But x2>>>x1 (since the solution is dilute).
So x1 can be neglected in the denominator.
Hence mole fraction of solute = x1/x2.
(8)
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