Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 35)
35.
At room temperature, the product [H+] [OH-] in a solution is 10-14 moles/litre. If, [OH-] = 10-6 moles/litre, then the pH of the solution will be
Discussion:
2 comments Page 1 of 1.
Ankita davane said:
9 years ago
pH + pOH = 14,
pOH = -log[OH] = -log[10^-6] = 6,
pH = 14 - pOH = 14 - 6 = 8,
pH = 8.
pOH = -log[OH] = -log[10^-6] = 6,
pH = 14 - pOH = 14 - 6 = 8,
pH = 8.
Nasir mumtaz said:
5 years ago
Thanks @Ankita.
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